What volume is occupied by a 1.50 mol sample of methane gas at a temperature of 0 °C and a pressure of 1 atm?
L
The volume occupied by a gas can be calculated using the ideal gas law equation:
PV = nRT
Where:
P = pressure (1 atm)
V = volume
n = number of moles (1.50 mol)
R = gas constant (0.08206 L atm/mol K)
T = temperature in Kelvin (0°C = 273 K)
We need to first convert the temperature to Kelvin by adding 273 to 0°C:
T = 0 + 273 = 273 K
Now we can plug in the values and solve for V:
(1 atm) * V = (1.50 mol) * (0.08206 L atm/mol K) * (273 K)
V = (1.50 mol * 0.08206 L atm/mol K * 273 K) / 1 atm
V = 33.56 L
Therefore, the volume occupied by a 1.50 mol sample of methane gas at a temperature of 0 °C and a pressure of 1 atm is 33.56 liters.