A sample of krypton gas at a pressure of 969 mm Hg and a temperature of 86 °C, occupies a volume of 6.88 liters. If the gas is cooled at constant pressure to a temperature of 38 °C, the volume of the gas sample will be
L.
To find the final volume of the gas sample, we can use the combined gas law formula:
P1V1/T1 = P2V2/T2
where:
P1 = initial pressure = 969 mm Hg
V1 = initial volume = 6.88 L
T1 = initial temperature = 86 °C + 273.15 = 359.15 K
P2 = final pressure = 969 mm Hg (since pressure is constant)
T2 = final temperature = 38 °C + 273.15 = 311.15 K
V2 = final volume (the unknown)
Plugging in the values:
969 mm Hg * 6.88 L / 359.15 K = 969 mm Hg * V2 / 311.15 K
V2 = (969 mm Hg * 6.88 L * 311.15 K) / (969 mm Hg * 359.15 K)
V2 = 2117.1128 L
Therefore, the volume of the gas sample at a temperature of 38 °C is approximately 2117.11 L.