(grade 10 work )
A particle has 3,98×10-¹³ of energy and has a wavelength of 5 ×10-¹³
Use the statement above
What is the speed of a photon
Calculate using the method of energy=planks constant × speed of light (over) wavelength
Given:
Energy = 3.98×10^-13 J
Wavelength = 5×10^-13 m
The formula to calculate the speed of light using energy, Plank's constant, and wavelength is:
Energy = Plank's constant (h) × Speed of light (c) / Wavelength (λ)
Rearranging the formula to solve for speed of light (c), we get:
c = Energy × Wavelength / Plank's constant
Plank's constant (h) is approximately 6.626 × 10^-34 J·s
Substitute the values into the formula:
c = (3.98×10^-13 J) × (5×10^-13 m) / (6.626 × 10^-34 J·s)
c = (1.99×10^-25 J·m) / (6.626 × 10^-34 J·s)
c = 3.00 × 10^8 m/s
The speed of light in a vacuum is approximately 3.00 × 10^8 m/s.