Triangle 1 has a side with 11.4 in and another side with 18 in
Triangle 2 has a side of 23.4 in and another side of x
Whats is the length of x in decimal form to the nearest hundredth
To find the length of side x in Triangle 2, we can first find the length of the third side in Triangle 1 using the Pythagorean theorem:
a^2 + b^2 = c^2
11.4^2 + 18^2 = c^2
129.96 + 324 = c^2
453.96 = c^2
c = √453.96
c ≈ 21.30
Now that we know the length of the third side in Triangle 1 is approximately 21.30, we can set up a proportion to find the length of side x in Triangle 2:
11.4 / 18 = 21.3 / x
Cross multiplying:
11.4x = 18 * 21.3
11.4x = 383.4
x = 383.4 / 11.4
x ≈ 33.57
Therefore, the length of side x in Triangle 2 to the nearest hundredth is approximately 33.57.