Propane
H2, molar mass = 2.016
C3H6 + H2 + C3Hg
Assuming 6.00 g of propene and 16.00 g of hydrogen are used, answer the following questions:
Part: 0 / 6
can be prepared by the reaction of propene
according to the following balanced equation:
C3H8, molar mass = 44.09
g
mol
g
mo1
C3H6, molar mass = 42.08
mol
with hydrogen
Part 1 of 6
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
moles of propene =
mol C3H6
To find the moles of propene used, we first need to convert the given mass of propene (6.00 g) to moles using the molar mass of propene (42.08 g/mol):
moles of propene = 6.00 g / 42.08 g/mol
moles of propene = 0.1426 mol
Therefore, 0.1426 moles of propene are used.