a 5kg block, resting on a rough horizontal table is connected by a light in extensible string passing over a light frictionless pulley to another block of mass 2 kg. the 2 kg block hangs vertically. a force of 60N is applied to the 5 kg block at an angle of 10 degrees to the horizontal, causing the block to accelerate to the left.
a) calculate the magnitude of the horizontal component of the 60N force
To calculate the magnitude of the horizontal component of the 60N force, we first need to find the component of the force that is acting in the horizontal direction. This can be calculated using trigonometry as follows:
Horizontal component = 60N * cos(10 degrees)
Horizontal component = 60N * cos(10 degrees)
Horizontal component = 60N * 0.9848
Horizontal component = 59.088N
Therefore, the magnitude of the horizontal component of the force is 59.088N.