a 5kg block, resting on a rough horizontal table is connected by a light in extensible string passing over a light frictionless pulley to another block mass of 2 kg. the 2 kg block hangs vertically. A force of 60N is applied to the 5 kg block at an angle of 10° to the horizontal, causing the block to accelerate to the left
a) calculate the magnitude of the vertical component of the 60N force
To calculate the vertical component of the 60N force, we first need to find the component of the force that is acting vertically and the component that is acting horizontally.
Vertical component: 60N * sin(10°) = 60N * 0.1736 ≈ 10.42 N
Therefore, the magnitude of the vertical component of the 60N force is approximately 10.42 N.