Calculate the concentration of the following solution .49.0grams of sulfuric acid in 2.5dm³of solution.
To calculate the concentration of the solution, we first need to determine the molarity of sulfuric acid:
The molar mass of sulfuric acid (H2SO4) is:
1 mol of H2SO4 = 2(1.01) + 32.06 + 4(16.00) = 98.08 g/mol
Next, we need to calculate the number of moles of sulfuric acid in 49.0 grams:
49.0 g / 98.08 g/mol = 0.499 moles
Finally, we can calculate the concentration (molarity) of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.499 moles / 2.5 dm³ = 0.2 mol/dm³ or 0.2 M
Therefore, the concentration of the solution is 0.2 mol/dm³ or 0.2 M.
Calculate the concentration of the following solutions 4.0gram of sodium hydroxide in 500cm³ of solution
To calculate the concentration of the solution, we first need to determine the molarity of sodium hydroxide (NaOH):
The molar mass of sodium hydroxide (NaOH) is:
1 mol of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol
Next, we need to calculate the number of moles of sodium hydroxide in 4.0 grams:
4.0 g / 40.00 g/mol = 0.1 moles
Next we need to convert the volume into liters:
500 cm³ = 500/1000 = 0.5 dm³
Finally, we can calculate the concentration (molarity) of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.1 moles / 0.5 dm³ = 0.2 mol/dm³ or 0.2 M
Therefore, the concentration of the solution is 0.2 mol/dm³ or 0.2 M.