how many moles of C2H6 are needed to form 0.16 mol of CO
To determine how many moles of C2H6 are needed to form 0.16 mol of CO, we need to first balance the chemical equation for the reaction of C2H6 (ethane) with O2 (oxygen) to produce CO (carbon monoxide) and H2O (water). The balanced equation is as follows:
2C2H6 + 7O2 → 4CO + 6H2O
From the balanced equation, we can see that 2 moles of C2H6 are required to produce 4 moles of CO. Therefore, the mole ratio is 2 moles C2H6 : 4 moles CO, or simplified to 1 mole C2H6 : 2 moles CO.
Given that we want to produce 0.16 mol of CO, we can set up a proportion:
1 mole C2H6 / 2 moles CO = x moles C2H6 / 0.16 moles CO
Solving for x:
x = (1 mole C2H6 / 2 moles CO) * 0.16 moles CO
x = 0.08 moles C2H6
Therefore, 0.08 moles of C2H6 are needed to form 0.16 mol of CO.