The anesthetic chloroform (CHCI3, molar mass=119.36 g/mol) can be prepared by the reaction of methane CH4 molar mass= 16.04 g/mol with chlorine according to the following balanced equation: CH4+3CI2 CHCI3+3HCI
Assuming 10.50g of methane and 20.50g of chlorine are used, answer the following questions:
How many moles of chlorine are used? Be sure your answer has the correct number of significant figures.
moles of chlorine 0.289 is not the correct significant figure
To find the number of moles of chlorine used in the reaction, we first need to calculate the molar mass of chlorine:
Cl2: 35.45 g/mol (molar mass of Cl) * 2 = 70.90 g/mol
Next, we convert the given mass of chlorine to moles:
20.50 g Cl2 * (1 mol Cl2 / 70.90 g Cl2) = 0.289 moles Cl2
Therefore, the moles of chlorine used in the reaction is 0.289 (to three significant figures).