The anesthetic chloroform (CHCI3, molar mass=119.36 g/mol) can be prepared by the reaction of methane CH4 molar mass= 16.04 g/mol with chlorine according to the following balanced equation: CH4+3CI2 CHCI3+3HCI
Assuming 10.50g of methane and 20.50g of chlorine are used, answer the following questions:
How many moles of chlorine are used? Be sure your answer has the correct number of significant figures.
moles of chlorine
To find the number of moles of chlorine used, we can first calculate the molar mass of chlorine (Cl2):
Molar mass of Cl2 = 35.45 g/mol (molar mass of Cl) * 2 = 70.90 g/mol
Next, we can convert the given mass of chlorine (20.50g) to moles:
moles of Cl2 = 20.50g / 70.90 g/mol = 0.289 mol
Therefore, 0.289 moles of chlorine are used in the reaction.