Propane (C3H8, molar mass=44.09g/mol) can be prepared by the reaction of propene C3H6 molar mass=42.08 g/mol) with hydrogen (H2, molar mass=2.016 g/mol) according to the following balanced equation: C3H6+H2 C3H8
Assuming18.50g of propene and 28.50 of hydrogen are used, answer the following questions:
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
How many moles of hydrogen are used? Be sure your answer has the correct number of significant figures.
To find the number of moles of propene used, we need to divide the given mass of propene by its molar mass:
Number of moles = mass / molar mass
Number of moles of propene = 18.50 g / 42.08 g/mol = 0.439 mol
To find the number of moles of hydrogen used, we need to divide the given mass of hydrogen by its molar mass:
Number of moles = mass / molar mass
Number of moles of hydrogen = 28.50 g / 2.016 g/mol = 14.14 mol