Propane (C3H8, molar mass=44.09g/mol) can be prepared by the reaction of propene C3H6 molar mass=42.08 g/mol) with hydrogen (H2, molar mass=2.016 g/mol) according to the following balanced equation: C3H6+H2 C3H8
Assuming18.50g of propene and 28.50 of hydrogen are used, answer the following questions:
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
To find the number of moles of propene used, we need to use the molar mass of propene and the given mass.
Moles of propene = mass of propene / molar mass of propene
Moles of propene = 18.50g / 42.08 g/mol
Moles of propene = 0.4391 mol
Rounding to the correct number of significant figures gives us:
Moles of propene = 0.44 mol