Given that f(x)=x−1%0D%0A%0D%0A(%0D%0A%0D%0A)%0D%0A=%0D%0A%0D%0A−%0D%0A1%0D%0A and g(x)=x2+3x−6%0D%0A%0D%0A(%0D%0A%0D%0A)%0D%0A=%0D%0A%0D%0A2%0D%0A+%0D%0A3%0D%0A%0D%0A−%0D%0A6%0D%0A , find (f+g)(2)%0D%0A(%0D%0A%0D%0A+%0D%0A%0D%0A)%0D%0A(%0D%0A2%0D%0A)%0D%0A .
To find (f+g)(2), we need to find the sum of f(2) and g(2).
First, let's find f(2):
f(x) = x - 1
f(2) = 2 - 1
f(2) = 1
Next, let's find g(2):
g(x) = x^2 + 3x - 6
g(2) = 2^2 + 3(2) - 6
g(2) = 4 + 6 - 6
g(2) = 4
Now we can find (f+g)(2) by adding f(2) and g(2):
(f+g)(2) = 1 + 4
(f+g)(2) = 5
Therefore, (f+g)(2) = 5.