What is the product of 4 square root 21 and 9 square root 6 in simplest radical form
To find the product of 4√21 and 9√6, we multiply the coefficients (4 and 9) and multiply the radicands (√21 and √6):
4√21 * 9√6 = 36 * √(21*6) = 36 √(126).
We can simplify the radical by factoring 126 into its prime factors: 2 * 3^2 * 7.
Therefore, the product in simplest radical form is: 36√(2 * 3^2 * 7) = 36 * 3√2 * √7 = 108√(2 * 7).
Simplifying further, we have: 108 * √(14) = 108√14.
So, the product of 4√21 and 9√6 in simplest radical form is 108√14.