Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other vat already contains 28 gallons and is continuing to fill at a rate of 4 gallons per minute. When will the two vats have the same amount of liquid?(1 point)
They will have the same amount of liquid after
let's call the time at which the two vats have the same amount of liquid as "t" minutes.
In "t" minutes, the first vat will have filled 6t gallons of liquid.
In "t" minutes, the second vat will have filled 28 + 4t gallons of liquid.
To find when the two vats have the same amount of liquid, we can set up the equation:
6t = 28 + 4t
Subtracting 4t from both sides, we get:
2t = 28
Dividing both sides by 2, we get:
t = 14
Therefore, the two vats will have the same amount of liquid after 14 minutes.