how do u graph the following:
Y=-2xsq'd-6x+3
Complete the squares
to get the standard form
y=a(x-h)^2+k
where (h,k) is the vertex, and
if a>0, the curve (parabola) is concave upwards, and if a<0, the curve is convex upwards.
y(x) = -2x²-6x+3
=-2(x+3/2)²+7.5
So a=-2, h=-3/4 and k=7.5
Graph the vertex (convex upwards, a=-2<0), and use a table of values of x-y to complete the graph.