Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it feels at a rate of 16 cans per minute the second machine has failed 104 cans of soup it fails cans at a rate of 13 cans per minute. Right and solve an equation to show when the two machines will have filled the same number of cans of soup. Use x as a variable
Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.
The first machine fills cans at a rate of 16 cans per minute. Therefore, after x minutes, it will have filled 16x cans of soup.
Similarly, the second machine fills cans at a rate of 13 cans per minute. Therefore, after x minutes, it will have filled 13x cans of soup.
Since we want to find the point at which the two machines have filled the same number of cans, we can set up the following equation:
16x = 13x
To solve this equation, we subtract 13x from both sides:
16x - 13x = 13x - 13x
3x = 0
Dividing both sides by 3:
x = 0
Therefore, the two machines will have filled the same number of cans of soup after 0 minutes.