A 200W laptop is connected to a 240v Ac line
1.calculate the RMS current flowing from the outlet
2.Determine the peak current
3.calculate the peak voltage
4.calculate the maximum power delivered from the Ac line
To calculate these values, we can use the formula:
Power (P) = Current (I) * Voltage (V)
1. Calculating the RMS current flowing from the outlet:
Since the power of the laptop is given as 200W and the voltage is 240V, we can rearrange the formula to solve for current:
I = P / V
I = 200W / 240V
I ≈ 0.833 A (rounded to three decimal places)
Therefore, the RMS current flowing from the outlet is approximately 0.833 A.
2. Determining the peak current:
The peak current can be calculated by multiplying the RMS current by the square root of 2 (sqrt(2)):
Peak Current (Ip) = RMS Current (Irms) * sqrt(2)
Ip = 0.833 A * sqrt(2)
Ip ≈ 1.178 A (rounded to three decimal places)
Therefore, the peak current is approximately 1.178 A.
3. Calculating the peak voltage:
The peak voltage can also be calculated using the formula:
Peak Voltage (Vp) = RMS Voltage (Vrms) * sqrt(2)
However, the RMS voltage is not provided in this scenario. Assuming it is the same as the supplied voltage (240V), we can calculate the peak voltage as follows:
Vp = 240V * sqrt(2)
Vp ≈ 339.411 V (rounded to three decimal places)
Therefore, the peak voltage is approximately 339.411 V.
4. Calculating the maximum power delivered from the AC line:
The maximum power delivered from the AC line can be determined using the formula:
Maximum Power (Pmax) = RMS Current (Irms) * RMS Voltage (Vrms)
Pmax = 0.833 A * 240V
Pmax ≈ 199.92 W (rounded to two decimal places)
Therefore, the maximum power delivered from the AC line is approximately 199.92 W.