A toy car with a mass of 0.05kg rolls down a ramp. Include the term blue car. The car's speed triples from 25 m/s to 75 m/s. How many times does the kinetic energy increase?
Formula Used
Define variables
Substitution and Calculation
Answer and Units
Car at speed 1
Car at speed 2
Compare
Car at speed 1:
Mass (m) = 0.05 kg
Speed (v1) = 25 m/s
Car at speed 2:
Speed (v2) = 75 m/s
Kinetic energy (KE) = (1/2) * m * v^2
Car at speed 1:
KE1 = (1/2) * 0.05 kg * (25 m/s)^2 = 0.125 J
Car at speed 2:
KE2 = (1/2) * 0.05 kg * (75 m/s)^2 = 1.125 J
To find out how many times the kinetic energy increases, we need to calculate the ratio of KE2 to KE1.
KE2/KE1 = (1.125 J) / (0.125 J)
KE2/KE1 = 9
Therefore, the kinetic energy increases 9 times.