What is the percent of H in H2O2?
The percent of H in H2O2 can be calculated by determining the molar mass of hydrogen (H) and the molar mass of hydrogen peroxide (H2O2), then dividing the molar mass of H by the molar mass of H2O2 and multiplying by 100.
The molar mass of hydrogen (H) is approximately 1.01 g/mol.
The molar mass of hydrogen peroxide (H2O2) can be calculated as follows:
(2 × molar mass of H) + (2 × molar mass of O) = (2 × 1.01 g/mol) + (2 × 16.00 g/mol) = 34.02 g/mol.
Now, divide the molar mass of H (1.01 g/mol) by the molar mass of H2O2 (34.02 g/mol):
(1.01 / 34.02) × 100 = 2.97%
Therefore, the percent of H in H2O2 is approximately 2.97%.