In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?(1 point)

Responses

0, 3, 9, 12
0, 3, 9, 12

9, 10, 11, 12
9, 10, 11, 12

8, 7, 6
8, 7, 6

9, 8, 7, 6

The solution to the inequality 18+2x≥36 is x≥9.

Therefore, the set of numbers where all the numbers are solutions of the inequality is 9, 10, 11, and 12.

So, the correct answer is:
9, 10, 11, 12

The inequality that could have solutions both greater than and less than 37 is the following:

x ≠ 37 (x not equal to 37)

This inequality allows for values of x that are both greater than and less than 37, as any value other than 37 would satisfy the inequality.

So, the correct answer is:
x≠37 (x not equal to 37)

To determine which inequality has solutions that include 12, 13, and 14, we can substitute those numbers into each of the given inequalities and see which ones satisfy the inequality.

Substituting 12, 13, and 14 into each inequality:

2x < 13+15:
2(12) < 13+15
24 < 28
This inequality is not satisfied by the numbers 12, 13, and 14.

2x ≥ 11+13:
2(12) ≥ 11+13
24 ≥ 24
This inequality is satisfied by the numbers 12, 13, and 14.

2x ≤ 12:
2(12) ≤ 12
24 ≤ 12
This inequality is not satisfied by the number 12.

2x ≥ 34−6:
2(12) ≥ 34-6
24 ≥ 34-6
24 ≥ 28
This inequality is not satisfied by the number 12.

Therefore, the inequality that has solutions including 12, 13, and 14 is:
2x ≥ 11+13

So, the correct answer is:
2x ≥ 11+13

I apologize for the mistake.

You are correct. The correct set of numbers where all the numbers are solutions to the inequality 60g > 3×5 is 1, 2, and 3.

So, the correct answer is:
1, 2, and 3

In which of the given sets of numbers are all the numbers solutions of 4x+7≠23 ? (1 point)

Responses

2, 3, 5, 6
2, 3, 5, 6

3, 4, 6, 7
3, 4, 6, 7

1, 2, 3, 4
1, 2, 3, 4

4, 5, 6, 7

To find the set of numbers where all the numbers are solutions to the inequality 4x+7≠23, we need to solve for x.

Subtracting 7 from both sides of the equation, we get 4x ≠16.

Dividing both sides of the equation by 4, we get x ≠4.

Therefore, the set of numbers where all the numbers are solutions to the inequality is 2, 3, 5, and 6.

So, the correct answer is:
2, 3, 5, 6

Which inequality could have solutions both greater than and less than 37?(1 point)

Responses

x≥37
x greater-than-or-equal-to 37

x≠37
x not equal to 37

x>37
x greater than 37

x<37

Which inequality has solutions that include 12, 13, and 14?(1 point)

Responses

2x<13+15
2 x less than 13 plus 15

2x≥11+13
2 x greater-than-or-equal-to 11 plus 13

2x≤12
2 x less-than-or-equal-to 12

2x≥34−6

In which of the following sets of numbers are all the numbers solutions to 60g>3×5 ?(1 point)

Responses

4, 5, and 6
4, 5, and 6

1, 2, and 3
1, 2, and 3

3, 4, and 5
3, 4, and 5

2, 3, and 4

no its 1,2 and 3