Use the equation for motion to answer the question. x=x0+v0t+12at2 An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s? (1 point) Responses 60 m 60 m 17 m 17 m 32 m 32 m 30 m
To determine the final position of the object after 1 second, we can plug in the given values into the equation.
Given:
x0 = 2 m (starting position)
v0 = 15 m/s (starting velocity)
t = 1 s (time)
Using the equation x = x0 + v0t + (1/2)at^2, where a is the acceleration:
x = 2 + 15*1 + (1/2)*a*(1)^2
Since the object is moving at a constant speed, the acceleration (a) is 0.
x = 2 + 15*1 + (1/2)*0*(1)^2
x = 2 + 15 + 0
x = 17
Therefore, the final position of the object after 1 second is 17 m.