During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point) Responses 120 N 120 N 20 N 20 N -20 N -20 N 20 m/s2
To solve this problem, we need to find the net force by considering both the magnitudes and directions of the forces involved.
The cue ball exerts a force of 70 N to the left, which we will denote as -70 N.
The four ball exerts a force of 50 N to the right, which we will denote as +50 N.
To find the net force, we need to add these two forces together. Since they are in opposite directions, we subtract the magnitudes:
Net force = -70 N + 50 N
Net force = -20 N
Therefore, the net force of this system is -20 N.