Qudratic formula for 2.8x^2-11x+28=0
To find the solutions of the quadratic equation 2.8x^2 - 11x + 28 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 2.8, b = -11, and c = 28.
Plugging in these values into the quadratic formula, we get:
x = (-(-11) ± √((-11)^2 - 4(2.8)(28))) / (2(2.8))
x = (11 ± √(121 - 313.6)) / 5.6
x = (11 ± √(-192.6)) / 5.6
Since the square root of a negative number results in a complex number, the solutions will also be complex numbers.
Thus, the solutions to the equation 2.8x^2 - 11x + 28 = 0 are:
x = (11 + √(-192.6)) / 5.6 and x = (11 - √(-192.6)) / 5.6