A coil of 600 turns is threaded by a flux of 8.0x10–5wb. If the flux is reduced to 3.0x10–wb in 0.0l5s, find the average induced emf
The average induced emf can be found using Faraday's law of electromagnetic induction, which states that the emf induced in a coil is equal to the rate of change of magnetic flux through the coil.
The rate of change of magnetic flux can be calculated using the equation:
ΔΦ = (Φ₂ - Φ₁) / Δt
Where:
ΔΦ is the change in magnetic flux
Φ₂ is the final magnetic flux
Φ₁ is the initial magnetic flux
Δt is the change in time
Given that:
Φ₁ = 8.0x10^-5 Wb
Φ₂ = 3.0x10^-5 Wb
Δt = 0.015 s
Substituting the values into the equation:
ΔΦ = (3.0x10^-5 - 8.0x10^-5) / 0.015
ΔΦ = -5.0x10^-5 / 0.015
ΔΦ = -3.33x10^-3 Wb/s
Since the number of turns in the coil is 600, the average induced emf can be calculated using the equation:
Emf = N * ΔΦ / Δt
Where:
Emf is the induced emf
N is the number of turns
Substituting the values into the equation:
Emf = 600 * (-3.33x10^-3) / 0.015
Emf = -20.0 V
Therefore, the average induced emf is -20.0 V.