A positive charge of 5.0×10−5 C
is 0.040 m
from a second positive charge of 2.0×10−6 C
. Calculate the force between the charges.(1 point)
Responses
5.6×10−2 N
5.6×10−2 N
5.6×102 N
5.6×102 N
1.4×10−2 N
1.4×10−2 N
2.3×101 N
To calculate the force between the charges, we can use the formula for the force between two charges:
F = k * |q1 * q2| / r^2
where F is the force, k is the electrostatic constant (9 * 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
Plugging in the values given:
F = (9 * 10^9 N m^2/C^2) * |5.0 * 10^(-5) C * 2.0 * 10^(-6) C| / (0.040 m)^2
Calculating the numerator:
|5.0 * 10^(-5) C * 2.0 * 10^(-6) C| = 10^-10 C^2
Plugging the values into the formula:
F = (9 * 10^9 N m^2/C^2) * (10^-10 C^2) / (0.040 m)^2
Calculating the denominator:
(0.040 m)^2 = 0.0016 m^2
Plugging the new values into the equation:
F = (9 * 10^9 N m^2/C^2) * (10^-10 C^2) / 0.0016 m^2
Calculating the numerator:
(9 * 10^9 N m^2/C^2) * (10^-10 C^2) = 0.9 N
Plugging the new values into the equation:
F = 0.9 N / 0.0016 m^2
Calculating the denominator:
0.9 N / 0.0016 m^2 = 562.5 N/m^2
Therefore, the force between the charges is approximately 562.5 N/m^2, or 5.6 × 10^2 N.