Original Poster Scale Drawing

left edge (in.) 36 ?
top edge (in.) 24 8
A local food organization puts out a healthy foods poster. The poster is in the shape of a rectangle, and its dimensions are given in the table. Alfredo wants to make a smaller version of the poster to hang up in the community center. He makes a scale drawing of the poster with the length of the top edge given in the table. What is the area of Alfredo’s scale drawing?

To find the area of Alfredo's scale drawing, we need to determine the dimensions of the smaller version of the poster and then calculate its area.

From the information given, we know that the length of the top edge of the scale drawing is 8 inches. However, the dimensions of the original poster are given in a ratio of 36:24, so we can use this ratio to determine the other dimensions.

If we set up a proportion using the ratio of the length of the original poster's top edge to its length, we get:

36 / 24 = 8 / x

Cross-multiplying, we get:

36x = 24 * 8

Simplifying:

36x = 192

Dividing both sides by 36, we find that x = 5.33...

Therefore, the length of the smaller version of the poster is approximately 5.33 inches.

To find the area of the scale drawing, we multiply the length and width:

Area = 5.33 inches * 8 inches ≈ 42.67 square inches.

Hence, the area of Alfredo's scale drawing is approximately 42.67 square inches.

Are you sure

Apologies for the mistake in my previous response. Let's recalculate the area of Alfredo's scale drawing correctly.

We are given the length of the top edge of the scale drawing as 8 inches. Using the given ratio of 36:24, we can determine the corresponding length of the left edge of the scale drawing.

Using the proportion:

36 / 24 = x / 8

Cross-multiplying:

36 * 8 = 24 * x
288 = 24x

Dividing both sides by 24 gives:

12 = x

Therefore, the length of the left edge of the scale drawing is 12 inches.

To calculate the area of the scale drawing, we multiply the length and width:

Area = length * width = 12 inches * 8 inches = 96 square inches.

Hence, the correct area of Alfredo's scale drawing is 96 square inches. Sorry for the earlier confusion and thank you for bringing it to my attention.