Two bowling balls of different masses collide while accelerating at 1.875 m/s2 . The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point) Responses 13.125 N to the right 13.125 N to the right 3.73 N to the right 3.73 N to the right 8.875 N to the right 8.875 N to the right 7.5 N to the left
To find the force that the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg, we can use Newton's second law of motion, which states that force is equal to mass times acceleration.
First, let's find the force acting on the 7 kg bowling ball. The mass is 7 kg, and the acceleration is 1.875 m/s^2. So, the force acting on the 7 kg bowling ball is:
Force_1 = mass_1 * acceleration = 7 kg * 1.875 m/s^2 = 13.125 N (to the right)
Now, according to Newton's third law of motion, every action has an equal and opposite reaction. So, the force exerted by the 7 kg bowling ball on the 4 kg bowling ball will be the same magnitude but in the opposite direction.
Therefore, the force that the bowling ball weighing 7 kg exerts on the bowling ball weighing 4 kg is 13.125 N (to the left).