The angles of a triangle measure (x+10)° , (x+20)° , and (x+30)° . Find the measure of the smallest angle.
In a triangle, the sum of the three angles is always 180 degrees. Therefore,
(x+10) + (x+20) + (x+30) = 180.
Simplifying, we have:
3x + 60 = 180.
Subtracting 60 from both sides, we get:
3x = 120.
Dividing both sides by 3, we have:
x = 40.
So the smallest angle is x + 10 = 40 + 10 = <<40+10=50>>50 degrees. Answer: \boxed{50}.