In which of the following sets of numbers are all the numbers solutions to 60g>3×5 ?(1 point)
Responses
4, 5, and 6
4, 5, and 6
1, 2, and 3
1, 2, and 3
3, 4, and 5
3, 4, and 5
2, 3, and 4
2, 3, and 4
To determine which set of numbers satisfies the inequality 60g > 3 × 5, we need to solve the inequality for each set of numbers.
For the first set of numbers (4, 5, 6), we get:
For g = 4: 60 × 4 > 3 ×5
240 > 15 (True)
For g = 5: 60 × 5 > 3 ×5
300 > 15 (True)
For g = 6: 60 × 6 > 3 ×5
360 > 15 (True)
Therefore, all the numbers in the set (4, 5, 6) satisfy the inequality.
For the second set of numbers (1, 2, 3), we get:
For g = 1: 60 × 1 > 3 ×5
60 > 15 (True)
For g = 2: 60 × 2 > 3 ×5
120 > 15 (True)
For g = 3: 60 × 3 > 3 ×5
180 > 15 (True)
Therefore, all the numbers in the set (1, 2, 3) satisfy the inequality.
For the third set of numbers (3, 4, 5), we get:
For g = 3: 60 × 3 > 3 ×5
180 > 15 (True)
For g = 4: 60 × 4 > 3 ×5
240 > 15 (True)
For g = 5: 60 × 5 > 3 ×5
300 > 15 (True)
Therefore, all the numbers in the set (3, 4, 5) satisfy the inequality.
For the fourth set of numbers (2, 3, 4), we get:
For g = 2: 60 × 2 > 3 ×5
120 > 15 (True)
For g = 3: 60 × 3 > 3 ×5
180 > 15 (True)
For g = 4: 60 × 4 > 3 ×5
240 > 15 (True)
Therefore, all the numbers in the set (2, 3, 4) satisfy the inequality.
In conclusion, all the numbers in all the given sets satisfy the inequality 60g > 3 × 5.