At a given temperature the vapor pressures of benzene and toluene are 183 mmHg and 59.2 mmHg, respectively. Calculate the total vapor pressure over a solution of benzene and toluene with Xbenzene = 0.580
To calculate the total vapor pressure, you can use Raoult's law, which states that the vapor pressure of a solution is equal to the mole fraction of each component multiplied by its vapor pressure at that temperature.
The mole fraction of benzene is given as Xbenzene = 0.580.
The vapor pressure of benzene is given as 183 mmHg.
The vapor pressure of toluene is given as 59.2 mmHg.
So, the total vapor pressure can be calculated as:
Total vapor pressure = Xbenzene * vapor pressure of benzene + (1 - Xbenzene) * vapor pressure of toluene
Total vapor pressure = (0.580 * 183 mmHg) + (1 - 0.580) * 59.2 mmHg
Total vapor pressure = (106.14 mmHg) + (0.420 * 59.2 mmHg)
Total vapor pressure ≈ 106.14 mmHg + 24.8 mmHg
Total vapor pressure ≈ 130.94 mmHg
Therefore, the total vapor pressure over the solution is approximately 130.94 mmHg.