a cyclist travels at a constant velocity of 4.5 m/s westward and then speeds up with a steady acceleration of 2.3 ms2 calculat the cyclists speed after accelerating for 5 seconds
We can use the equation of motion to solve this problem. The equation of motion for constant acceleration is:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Before accelerating, the cyclist is traveling at a constant velocity of 4.5 m/s westward, so the initial velocity (u) is 4.5 m/s.
The acceleration (a) is given as 2.3 m/s^2.
The time (t) for which the cyclist accelerates is 5 seconds.
Using the equation of motion, we can calculate the final velocity (v) after accelerating for 5 seconds:
v = u + at
v = 4.5 m/s + (2.3 m/s^2) * 5 s
v = 4.5 m/s + 11.5 m/s
v = 16 m/s
Therefore, the cyclist's speed after accelerating for 5 seconds is 16 m/s.