what value of x will make x,63,65 a pythagorean triple?

To determine the value of x that will make x, 63, and 65 a Pythagorean triple, we can use the Pythagorean theorem. According to the theorem, in a Pythagorean triple, if a, b, and c are positive integers, then:

a^2 + b^2 = c^2

In this case, x is the unknown value, and we are given that the triple is x, 63, and 65. Applying the Pythagorean theorem:

x^2 + 63^2 = 65^2

Simplifying the equation:

x^2 + 3969 = 4225

Subtracting 3969 from both sides:

x^2 = 256

Taking the square root of both sides:

x = ± 16

Therefore, the two values of x that will make x, 63, and 65 a Pythagorean triple are x = 16 and x = -16.

and -16 is a strange measure of the leg of a right triangle.

You are correct. In the context of a Pythagorean triple, we typically consider positive integer values for the sides of a right triangle. Therefore, in this case, the value of x that will make x, 63, and 65 a Pythagorean triple is x = 16.