use the remainder theorem to find the remainder when p(x)=x^4+9x^3+2x^2-x+5 is divided by x-2 show your steps without exampling it with words
To find the remainder when p(x) = x^4 + 9x^3 + 2x^2 - x + 5 is divided by x - 2, we can use the remainder theorem.
First, we substitute x - 2 into p(x) and calculate the value of p(2):
p(2) = (2)^4 + 9(2)^3 + 2(2)^2 - 2 + 5
= 16 + 9(8) + 2(4) - 2 + 5
= 16 + 72 + 8 - 2 + 5
= 99
Now, we know that the remainder when p(x) is divided by x - 2 is equal to p(2), which is 99.