Use the image to answer the question.
An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid downward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma 1 right parenthesis and left parenthesis 1 comma negative 4 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
Responses
y=−5x+1
y=5x+1
y=−5x−1
−5x−y=−1
To find the equation of the line in slope-intercept form, we need to determine the slope and the y-intercept.
Using the two plotted points (0,1) and (1,-4), we can calculate the slope (m) as the change in y divided by the change in x:
m = (y2 - y1) / (x2 - x1)
m = (-4 - 1) / (1 - 0)
m = -5/1
m = -5
The y-intercept (b) is the value of y when x is equal to 0. From the given plotted point (0,1), we can determine that b = 1.
Now we can write the equation of the line in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept:
y = -5x + 1
Therefore, the equation of the line in slope-intercept form is y = -5x + 1.