What is the magnitude of the cart’s acceleration? a. 0.50 m/s 2 b. 3.5 m/s 2 c. 3.0 m/s 2 d. 4.0 m/s 2 A constant eastward horizontal force of 70 newtons is applied to a 20 kilogram cart moving toward the east on a level floor. The frictional force on the cart has a magnitude of 10 newtons. 4. Which of the following correctly freebody diagrams correctly represents the forces acting on the cart?
The magnitude of the cart's acceleration can be determined using Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Force applied to the cart (Fapplied) = 70 N
Mass of the cart (m) = 20 kg
Frictional force (Ffriction) = 10 N
The net force acting on the cart can be calculated as:
Net force (Fnet) = Fapplied - Ffriction
Fnet = 70 N - 10 N
Fnet = 60 N
Now, we can use Newton's second law to calculate the magnitude of the cart's acceleration (a):
Fnet = m * a
60 N = 20 kg * a
a = 60 N / 20 kg
a = 3.0 m/s^2
Therefore, the magnitude of the cart's acceleration is 3.0 m/s^2.
As for the second part of the question, without visual representation it is not possible to provide a correct answer.