Find the slope of a line perpendicular to the line whose equation is 2, x, minus, 12, y, equals, minus, 1202x−12y=−120
To find the slope of a line perpendicular to another line, we need to find the negative reciprocal of the slope of the given line.
The given line is in the form of Ax + By = C, where A, B, and C are constants. In this case, the equation is 2x - 12y = -120.
To find the slope of this line, we can rearrange the equation into slope-intercept form, y = mx + b, where m is the slope of the line.
2x - 12y = -120
-12y = -2x - 120
y = (2/12)x + 10
From this equation, we can see that the slope of the given line is 2/12 or 1/6.
The slope of a line perpendicular to this line would be the negative reciprocal of 1/6, which is -6/1 or -6.