A particle starts from rest and moves with a constant acceleration of 0.5ms-².calculate the time taken by the body to cover a distance of 25m
To calculate the time taken by the particle to cover a distance of 25m, we can use the following kinematic equation:
\(s = ut + \frac{1}{2}at^2\),
where s is the distance, u is the initial velocity (which is zero in this case since the particle starts from rest), a is the acceleration, and t is the time taken.
Plugging in the given values:
\(25 = 0\times t + \frac{1}{2}\times 0.5 \times t^2\).
Simplifying this equation:
\(25 = 0.25t^2\).
Rearranging the equation:
\(t^2 = \frac{25}{0.25}\).
\(t^2 = 100\).
Taking the square root of both sides:
\(t = \sqrt{100}\).
\(t = 10\) seconds.
Therefore, the time taken by the particle to cover a distance of 25m is 10 seconds.