find the value of y so that the line passing through the two points has the given slope.
(8.y), (2,-3), m=1/2
y= mx+b
y=.5x+b
-3=.5*2+b solve for b at that point.
then go to the first point, and solve for y.
(4,7)and (8,10)
To find the value of y so that the line passing through the two points (8, y) and (2, -3) has the given slope of 1/2, we can use the slope formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
Let's use the formula and solve for y:
1/2 = (-3 - y) / (2 - 8)
First, simplify the expression on the right side of the equation:
1/2 = (-3 - y) / (-6)
Now, cross-multiply:
(-3 - y) * 2 = 1 * (-6)
Simplify this equation further:
-6 - 2y = -6
Add 6 to both sides of the equation:
-2y = 0
Divide both sides of the equation by -2:
y = 0
Therefore, the value of y is 0, so the line passing through the two points (8, y) and (2, -3) will have the slope of 1/2.