What is the vertex of this equation?
y = (x + 4)^2 -6
Pay attention to negative signs!
A) (4, -6)
B) (4, 6)
C) (-4, -6)
D) (-4, 6)
The vertex form of a quadratic equation is given by y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.
In this case, the equation is y = (x + 4)^2 - 6. Comparing this to the vertex form, we can identify that h = -4 and k = -6.
Therefore, the vertex of the equation is (-4, -6).
Answer: C) (-4, -6)