Solve the system by substitution.
minus, 9, x, minus, 10, y, equals, 12
−9x−10y=
12
minus, 3, x, plus, 3, equals, y
−3x+3=
y
To solve the system by substitution, we need to solve one of the equations for one variable and substitute that expression into the other equation.
From the second equation, we can solve for y:
y = -3x + 3
Now we can substitute this expression into the first equation:
-9x - 10(-3x + 3) = 12
Solving this equation will give us the value of x:
-9x + 30x - 30 = 12
21x - 30 = 12
21x = 42
x = 2
Now we can substitute this value of x into the second equation to find y:
y = -3(2) + 3
y = -6 + 3
y = -3
Therefore, the solution to the system of equations is x = 2 and y = -3.