Solve the system by substitution: 3x+10y=31 2x+10=y
We can solve the system of equations by substitution. We start by solving the second equation for y:
2x + 10 = y
Next, we substitute this value of y into the first equation:
3x + 10(2x + 10) = 31
Simplifying, we get:
3x + 20x + 100 = 31
Combining like terms, we have:
23x + 100 = 31
Subtracting 100 from both sides, we get:
23x = -69
Dividing both sides by 23, we find:
x = -3
Now, we substitute this value of x back into the second equation to solve for y:
2(-3) + 10 = y
Simplifying, we get:
-6 + 10 = y
y = 4
Therefore, the solution to the system of equations is x = -3 and y = 4.