Executives for a car dealership are interested in the sales for the type of vehicle, SUV or truck, and the type of power train, two-wheel drive (2WD), four-wheel drive (4WD), or all-wheel drive (AWD). The data from the sales of 165 vehicles are displayed in the two-way table.
A 3-column table with 3 rows. Column 1 has entries 2 wheel drive, 4 wheel drive, all wheel drive. Column 2 is labeled S U V with entries 10, 23, 52. Column 3 is labeled Truck with entries 6, 74, 0. The columns are titled Vehicle type and the rows are titled power train.
A vehicle is randomly selected. Let S be the event that the vehicle is an SUV and let D be the event that the vehicle has 4WD. What is the value of P(S and DC)?
0.04
0.23
0.38
0.41
To find the probability of both events occurring (P(S and D)), we need to find the intersection of the two events, which is the number of vehicles that are SUVs and have 4WD.
According to the table, there are 23 SUVs with 4WD.
To calculate the probability, we use the formula:
P(S and D) = Number of outcomes in the intersection / Total number of outcomes
The total number of outcomes is the total number of vehicles, which is 165.
P(S and D) = 23 / 165
P(S and D) ≈ 0.1394
Therefore, the value of P(S and D) is approximately 0.14.