A tennis player hits a 0.1 kg tennis ball with her racket from the north end of a quart. Her racket was traveling at 65 km/h. The ball accelerated at a rate of 10 m/s squared the ball hits the floor on the south end of the tennis court the floor sends the ball towards the tennis players opponent with the same acceleration. How much force did the floor on the south end of the Court exert on the ball
To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the ball (m): 0.1 kg
Acceleration (a): 10 m/s^2
We need to find the force (F).
Using the formula F = m * a, we can substitute the given values:
F = 0.1 kg * 10 m/s^2
F = 1 kg⋅m/s^2
Therefore, the floor exerts a force of 1 Newton on the ball.