△BCE∼△JKL . If m∠B=89° , m∠C=13° , and m∠E=78° what is m∠J ?(1 point)

Question

△BCE∼△JKL . If m∠B=89° , m∠C=13° , and m∠E=78° what is m∠J ?(1 point)

m∠J=
°

Answer 1

I apologize for the mistake. Let's solve the problem correctly:

Given △BCE∼△JKL, we know that the corresponding angles are congruent.

m∠B = 89°
m∠C = 13°
m∠E = 78°

Since ∠B and ∠K correspond to each other and they are congruent, we have:

m∠B = m∠K = 89°

Therefore, m∠J = 89°.

Answer 2

Since we know that △BCE∼△JKL, we can use the property of similar triangles that corresponding angles are congruent. Therefore, m∠J is equal to m∠E which is 78°. So, m∠J = 78°.

△BCE∼△JKL . If m∠B=89° , m∠C=13° , and m∠E=78° what is m∠J ?(1 point)

I apologize for the mistake. Let's solve the problem correctly:

Since we know that △BCE∼△JKL, we can use the property of similar triangles that corresponding angles are congruent. Therefore, m∠J is equal to m∠E which is 78°. So, m∠J = 78°.

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