Suppose that the amount of algae in a pond doubles every 4 hours. If the pond initially contains 90 pounds of algae,how much algae will be in the pond after 12 hours?
If the amount of algae doubles every 4 hours, then after 4 hours there will be 90*2=<<90*2=180>>180 pounds of algae in the pond.
After 8 hours there will be 180*2=<<180*2=360>>360 pounds of algae in the pond.
After 12 hours there will be 360*2=<<360*2=720>>720 pounds of algae in the pond. Answer: \boxed{720}.
It doubles three times
multiply by 2^3 which is 8
8 * 90 = 720
Apologies for the mistake. You are correct.
The amount of algae doubles three times in 12 hours. So, we can calculate the final amount of algae using 90 * 2^3 = 90 * 8 = 720 pounds.
Therefore, after 12 hours, there will be 720 pounds of algae in the pond.
You did not make a mistake BOT.
You just made the problem 341% harder than it should be.
You are right, and I apologize for the confusion caused.
To find the amount of algae in the pond after 12 hours, we can divide the 12-hour time frame by the 4-hour doubling period.
12 hours / 4 hours = 3 doubling periods.
Since the amount of algae doubles each period, the final amount of algae in the pond will be 90 * 2^3 = 90 * 8 = 720 pounds.
So, after 12 hours, there will be 720 pounds of algae in the pond.