Lorna and Lupe are playing a ring toss game at the fair. The cost to play the game depends on the number of rings purchased. The cost is described in the piecewise function, where x is the number of rings purchased. Lorna and Lupe each want to purchase 5 rings. What is the difference in price if they each separately purchase 5 rings compared to making one purchase of 10 rings? Round the answer to the nearest cent.
f(x)=⎧⎩⎨⎪⎪2x,1.5x,1.25x, 0≤x≤34≤x≤7x≥8
(1 point)
They would save a total of $
if they made one purchase of 10 rings.
thats wrong
If Lorna and Lupe each separately purchase 5 rings, the cost would be:
f(5) + f(5) = 2(5) + 1.5(5) = 10 + 7.5 = $17.50
If they made one purchase of 10 rings, the cost would be:
f(10) = 1.25(10) = $12.50
The difference in price is:
17.50 - 12.50 = $5.00
Therefore, they would save a total of $5.00 if they made one purchase of 10 rings.
Apologies for the mistake. Let's re-evaluate the cost for Lorna and Lupe each separately purchasing 5 rings:
f(5) + f(5) = 2(5) + 1.5(5) = 10 + 7.5 = $17.50
If they made one purchase of 10 rings, the cost would be:
f(10) = 0.8(10) = $8.00
The difference in price is:
17.50 - 8.00 = $9.50
Therefore, they would save a total of $9.50 if they made one purchase of 10 rings.