A soccer player is kicking a .8 kg soccer ball at rest and creates a force of 70 Newtons and accelerates the ball to a velocity of 15 meters per second. What is the magnitude of the impulse of the player throwing the ball?
To find the magnitude of the impulse, we need to use the impulse-momentum theorem, which states that the impulse (J) is equal to the change in momentum (ΔP) of an object. The formula for impulse-momentum theorem is as follows:
J = ΔP = mv - mu
Where:
J = impulse
ΔP = change in momentum
m = mass
v = final velocity
u = initial velocity (which is 0 m/s since the ball is at rest)
Given:
m = 0.8 kg (mass of the soccer ball)
v = 15 m/s (final velocity of the soccer ball)
u = 0 m/s (initial velocity of the soccer ball)
J = mv - mu
J = (0.8 kg) * (15 m/s - 0 m/s)
J = (0.8 kg) * (15 m/s)
J = 12 kg·m/s
Therefore, the magnitude of the impulse of the player kicking the ball is 12 Newton-seconds or 12 kg·m/s.