Triangle XYZ is translated down 4 units and to the left 8 units. The length of side XY is 10 units. What is the length of side X′Y′ ?
If triangle XYZ is translated down 4 units and to the left 8 units, then the coordinates of X' can be found by subtracting 8 from the x-coordinate of X and subtracting 4 from the y-coordinate of X. Let's assume the coordinates of X are (x1, y1). Therefore, the coordinates of X' will be (x1-8, y1-4).
Since side XY has length 10 units, we can find the length of X'Y' by using the distance formula.
Distance formula: √((x2-x1)^2 + (y2-y1)^2)
The coordinates of Y' will be 8 units to the left of the coordinates of Y (assuming Y has coordinates (x2, y2)). Therefore, the coordinates of Y' will be (x2-8, y2).
Substituting the coordinates into the distance formula, we get:
X'Y' = √((x2-x1+8)^2 + (y2-y1+4)^2)
Without additional information about the coordinates of X and Y or the shape of the triangle, we cannot determine the length of X'Y'.
well, there has to be an answer so i will say the question again
Triangle XYZ is translated down 4 units and to the left 8 units. The length of side XY is 10 units. What is the length of side X′Y′ ?
Apologies for the confusion. Let's proceed with the given information.
The length of side XY is 10 units. When triangle XYZ is translated down 4 units and to the left 8 units, the length of side XY remains the same. Translations do not change the lengths of the sides.
Therefore, the length of side X'Y' is also 10 units.